Example.
Splitting the first confactor for P(E|A,B,C,D) in Figure
* on Y gives two confactors:
a &y,
B | E | Value |
true | true | 0.55 |
true | false | 0.45 |
false | true | 0.3 |
false | false | 0.7 |
|
|
a &~ y,
B | E | Value |
true | true | 0.55 |
true | false | 0.45 |
false | true | 0.3 |
false | false | 0.7 |
|
|
Example.
Splitting the first confactor for P(B|Y,Z) in Figure
* on A gives two confactors:
a &y,
B | Z | Value |
true | true | 0.77 |
true | false | 0.17 |
false | true | 0.23 |
false | false | 0.83 |
|
|
~ a &y,
B | Z | Value |
true | true | 0.77 |
true | false | 0.17 |
false | true | 0.23 |
false | false | 0.83 |
|
|
The reason that we may want to do these two splits is that now we can
multiply confactors (*) and (*).